Aşk ve Gurur by Jane Austen

By Jane Austen

Aşk ve Gurur, taşralı bir beyfendinin kızı olan Elizabeth Bennett ile varlıklı ve soylu toprak sahibi Fitzwilliam Darcy arasındaki çatışmayı anlatır. Gerçi Jane Austen bu iki karakteri birbirlerinin tuzağına düşmüş kişiler gibi sunar, ama "ilk izlenim"i tersine çevirmekte gecikmez: Soyluluk ve servetten kaynaklanan "gurur" ile elizabeth'in ailesinin soylu olmayışı karşısında beslediği "önyargı", Darcy'yi mesafeli davranmak zorunda bırakır. Elizabeth'in davranışında da hem özsaygının uyandırdığı "gurur", hem de Darcy'nin züppeliği karşısındaki "önyargı" etkili olur. Zeki ve coşkulu Elizabeth yalnızca Austen'ın en çok sevdiği kadın kahramanı değil, aynı zaman bütün İngiliz edebiyatının en çok ilgi uyandıran kadın roman kişiliklerinden biridir. Sıradan insanların günlük yaşamlarını işleyerek romana ilk kez belirgin bir glossy nitelik kazandıran Austen'ın en sevilen romanlarından biri olan Aşk ve gurur'u, Nihal Yeğinobalı'nın yetkin Türkçesiyle sunuyoruz.

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9) with F(m) = m(1) . m(2). 2). The fact that c(t) is simply the sum of two Hopfield c-functions and F(m) = m(1)·m(2) suggests that the symmetry between the S- and the O"-variables is not broken and that fLittle(ß) = 2fHopfieJd(ß). 13a, 28]. 8) with F(m) = m(l) . m(2), the fixed-point equation for m = (m(l) , m(2» is 39 m(1) = (~tanh(ßm(2). ~»), m(2) = (~tanh(ßm(l) . 15) . 13a] o ~ (m(l) - m(2» . (m(1) _ m(2» = (m(I). ~ - m(2) . 16) since (x - y)[tanh(ßy) - tanh(ßx)] ~ O. So m(l) = m(2) == m and the S - a symmetry is not broken.

In a retrieval state, m Jl = m for some J-l while the other overlaps vanish. 6) has gone and v-;;; C = {211 - CI exp{ -[m(1 - C)]2 /2a} . 5) As a ~ 0, C converges to zero at an exponential rate. 6) 27r exp(-I/a) . 02 we would get s ~ -3 X 10-23 , which is extremely near to zero indeed. 49 X 10-3, which is also quite elose to zero, the exact value. We now consider the critical storage ratio ac at zero temperature more elosely. 138. 001. 967. 5 % ) of errors, which indeed do occur. 144. 9%. These improvements, though quite striking, are marginal compared to the replica-symmetric result.

38,41,42]. We now turn to the phase diagram, Fig. 2, which has been obtained by Amit et al. [1. 13c]. As a function of a, there are three main critical lines, namely, Tg(a), TM(a), and Tc(a). As we lower the temperature, we first pass Tg and then TM, provided that a < a c • Direcdy below TM the retrieval states are metastable. 051, we also pass a third line, Tc, below which the retrieval states are globally stable. 2. Phase diagram of the Hopfield model. At Tg• the spin-glass phase appears. Directly below TM.

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